(w-2)^2=2w^2+4w+16

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Solution for (w-2)^2=2w^2+4w+16 equation: 



(w-2)^2=2w^2+4w+16

We move all terms to the left:

(w-2)^2-(2w^2+4w+16)=0

We get rid of parentheses

-2w^2+(w-2)^2-4w-16=0

We add all the numbers together, and all the variables

-2w^2-4w+(w-2)^2-16=0

We move all terms containing w to the left, all other terms to the right

-2w^2-4w+(w-2)^2=16

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